Question

4(n-1)^2-4(n-1)-3 solve​

Answer 1

4(n - 1)² - 4(n - 1) - 3

= 4(n - 1)² - 4(n - 1) + 1 - 4

= [2(n - 1)]² - 2[2(n - 1)](1)+ (1)² - (2)²

= [2(n - 1) - 1]² - (2)²

= (2n - 2 - 1)² - (2)²

= (2n - 3)² - (2)²

= [(2n - 3) - (2)][(2n - 3) + (2)]

= (2n - 3 - 2)(2n - 3 + 2)

= (2n - 5)(2n - 1).