Question

4^n + 6^n = 9^n
Solve for the values of n

Answer 1

Answer:

the question is incorrect

Step-by-step explanation:

as we all know 4^n and 6^n (for any value of n whether it is negative,positive, in decimals) is always even no. and

even no. + even no. = even no.

and 9^n (for any value of n) is always odd

so even +even is not equals to odd

hence, the question is wrong.

hope u understand the concept

Answer 2

Either n = 0 or n = 1.

• In mathematics, an index (or indexes) is the power or exponent that is added to a number or variable. A constant is a number that cannot be altered. As opposed to a fixed quantity, a variable quantity's value can be altered or assigned any number. In algebra, indices are discussed in terms of numerical values.
• An index can be assigned to a number or variable. A value raised to the power of a variable's (or a constant's) value is its index. The exponents or powers are other names for the indices. The index instructs a certain integer or a certain base to be multiplied by itself a specified number of times, where the number of times is determined by the index raised to the base. It is a condensed way of expressing large sums of information and calculations.

Here, according to the given information, we are given that,

$4^{n} +6^{n} =9^{n}$

Or, $2^{n}( 2^{n}+3^{n})=9^{n}$

Or, $2^{n}( 2^{n}+3^{n})=3^{2n}$

Or, $\frac{2^{n}( 2^{n}+3^{n})}{3^{2n}} =\frac{2}{3} ^{0}$

Now, either n is 0 or $\frac{2}{3} ^{n} +1 = 1$.

This gives, n = 1.

hence, either n = 0 or n = 1.

Learn more here

https://brainly.in/question/40644615

#SPJ3