Question

4 n square minus 8 n and + 3 please factorise the following

Answer 1

Answer:

Step-by-step explanation

Answer 2

$4n^2 - 8n + 3 = (2n - 1)(2n - 3)$

Solution:

Given that, we have to factorize:

$4n^2 - 8n + 3$

We have to write the above equation as product of factors

From given,

$4n^2 - 8n + 3$

$\text{Split the middle term } \\\\4n^2 - 2n - 6n + 3$

$\mathrm{Break\:the\:expression\:into\:groups}\\\\\left(4n^2-2n\right)+\left(-6n+3\right)$

$\mathrm{Factor\:out\:}2n\mathrm{\:from\:}4n^2-2n$

$2n(2n - 1) + (-6n + 3)\\\\\mathrm{Factor\:out\:}-3\mathrm{\:from\:}-6n+3\\\\ 2n(2n - 1) - 3 (2n - 1)\\\\\mathrm{Factor\:out\:common\:term\:}2n-1\\\\\left(2n-1\right)\left(2n-3\right)$

Thus the given expression is factored

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