Question

4. On tuming a comer a car driver driving at 36 kmh
finds a child on the road 55 m ahead. He imme
diately applies brakes, so as to stop within 5 m of the
child. Calculate the retardation produced and the
time taken by the car to stop.





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Answer 1

Explanation:

u = 36km/hr i.e. 10m/s

v = 0m/s

s = 55 - 5 = 50m

a = ?

t = ?

By applying 3rd equation of motion

i.e. v^2 - u^2 = 2as

we get, 0^2 - (10)^2 = 2(50)a

-100 = 100a

a = -1m/s^2

this is retardation due to -ve value

Now, By applying 1st law of motion

i.e. v = u + at

we get, 0 = 10 + (-1)t

-10 = -t

t = 10 seconds

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