Question

4. One of the two digits of a two digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?

Answer 1

hye

==============================



 One of the two digits of a two digit number is three times the other digit.

=> let digits at tens place be (10)3x

=>digit at ones place be x

=>so the original number = (10)3x+x

                                             = 31x

so original number is 31 x

now when the interchange the digits of this two-digit number and add the resulting number to the original number, you get 88

=>so the interchanged number is 

=>[10]x +3x 

=>  13x 

now lets from an equation


=> 31x +13x = 88

=> 44x = 88

=>x=88/44 = 2

therefore lets substitute the values

=>orignal number is =(10)3x+x

since x is 2,

=>(10)3*2+2

=>60+2

=>62 is  the orginal number 

=====================

hope it helps u,.....................