Question

. 4 pipes can fill a tank in 15,20,30 and 60 hours respectively. If pipe A opened at 6am, B opens at 7 am, pipe C at 8 am and Pipe D at 9 am. At what time tank will be filled

Answer 1

1pm

Step-by-step explanation:

1 st pipe=15 hours

1 hour = 1/15 of tank

similarly,

2 nd pipe=1/20

3rd pipe =1/30

4th pipe =1/60

Time taken by 1st pipe = t

time taken by 2nd pipe = (t-1) { 1 hour later}

similarly

time taken by 3 rd pipe = t-2 hour

time taken by 4th pipe = t-3 hour

All pipe can fill the tank so we obtain an equation :

t/15+(t-1)/20+(t-2)/30 +(t-3)/60= 1

taking LCM

4t+3t-3+2t-4+t-3/60 = 1

10 t - 10 = 60

10 t = 60 + 10

10 t = 70

t = 70/10

t = 7 hours

1st pipe was opened at 6 am so,

6 am +. 7 hours = 1 pm

the tank will be filled at 1 pm .

I hope this may help you

Answer 2

Answer:

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Step-by-step explanation:

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