4. PQR is an isosceles triangle with
PQ = PR = 7 cm and QR = 12 cm. PS is
perpendicular to QR and RT is
perpendicular to PQ. If the length of PS
is 5 cm, find the area of PQR. What
will be the length of RT?
Answers
answers are in pic that i have attached
hope this helps...
Given : isosceles triangle with pq = pr = 7 cm and qr = 12 cm.
Ps is perpendicular to qr and
rt is perpendicular to pq.
the length of ps is 5 cm,
To find : the area of triangle pqr.
length of rt?
Solution:
isosceles triangle with pq = pr = 7 cm and qr = 12 cm.
Ps is perpendicular to qr
Area of Δpqr = (1/2) qr * ps
= (1/2) * 12 * 5
= 30 cm²
Area of Δpqr = (1/2) * pq * rt
= (1/2) * 7 * rt = 30
=> rt = 60/7 cm
But there is mistake in Data
as qr = 12 cm
=> qs = rs = 12/2 = 6 cm
ps = 5 cm
=> pq = qr = √6² + 5² = √61 = 7.81 cm not 7 cm
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