(4) Prove that any non-isosceles trapezium
is not cyclic
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To prove that any given quadrilateral is cyclic, we need to prove that its opposite angles are supplementary (i.e. they add up to 180˚). We need to prove that ∠BAD + ∠BCD = 180 and ∠ADC + ∠ABC = 180˚. Start by constructing two perpendiculars, AF and BE, from segment AB to segment CD.
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