4. Prove that
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let us assume 5√3 is rational number and can be written in the form a/b where b is not equal to 0
then 5√3=(a/b)
√3= (a/5b)
now √ 3 is irrational as we know but RHS is rational which cannot be true so this is a contradiction to our assumption therefore we can say that 5√3 is irrational.
hope it HELPS
then 5√3=(a/b)
√3= (a/5b)
now √ 3 is irrational as we know but RHS is rational which cannot be true so this is a contradiction to our assumption therefore we can say that 5√3 is irrational.
hope it HELPS
VijayaLaxmiMehra1:
its not a proper step
its the est way i know. you have to contradict the assumption. because we have to make use of the fact that √3 is irrational
I'm not asked with you
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ur handwriting is not good
I can't understand
what are you talking its totally understandable
its not a proper step
its the proper step i think you should use it as your answer.
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