4) raj divided 50 into two parts such that the sum of their reciprocal is 1/12, we get the parts as : a. 28, 22 b. 24, 36 c. 20, 30
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Let one number be x
the other number will be 50-x
1/x + 1/(50-x)= 1/12
50-x+x = x(50-x)/12
600 = 50x-x^2
x^2-50x+600=0
x^2-30x-20x+600=0
x(x-30)-20(x-30)=0
(x-30)(x-20)=0
x= 20 or 30
the numbers are 20 and 30
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Answer:
Step-by-step explanation:
x+y=50
1\x+1/y=12
x+y/xy=1/12
12(x+y)=xy
xy=600
we know that x+y is 50
and x*y is 600
when we know the sum and product of two numbers, check with the factors of product of the two numbers
600=2*300
2+300!=sum
as like
600=3*200!= sum
600=20*30
.....................
20+30=50
50=sum
so 20 and 30 are the numbers
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