4 sin^2 60 degree + 3 tan^2 30 degree-8 Sin 45 Degree cos 45 degree.
Answers
Answered by
44
the correct answer is:
= 4*(✓3/2)²+3*(1/✓3)²-8(1/✓2)(1/✓2)
= 4*(3/4)+3*(1/3)-8*(1/2)
= 3+1-4
= 0
= 4*(✓3/2)²+3*(1/✓3)²-8(1/✓2)(1/✓2)
= 4*(3/4)+3*(1/3)-8*(1/2)
= 3+1-4
= 0
Attachments:
Ruhanika105:
oh yes
it can't be edited
if i would have written thn i could edit it
hey friend answer is wrong in the picture
= 4*(✓3/2)² + 3*(1/✓3)²- 8*(1/✓2)(1/✓2) = 4*3/4 + 3*1/3 -8*1/2 =3+1-4=4-4=0
Answered by
62
Holla
Given
4sin²60° + 3tan²30° - 8sin45° . cos45°
4 . ( √3 / 2 )² + 3 ( 1 /√3 )² - 8 ( 1 /√2 ) . ( 1 /√2 )
= 4 × 3 / 4 + 3 × 1 / 3 - 8 × 1 / 2
= 3 + 1 - 4
= 3 - 3
= 0
====================================
Given
4sin²60° + 3tan²30° - 8sin45° . cos45°
4 . ( √3 / 2 )² + 3 ( 1 /√3 )² - 8 ( 1 /√2 ) . ( 1 /√2 )
= 4 × 3 / 4 + 3 × 1 / 3 - 8 × 1 / 2
= 3 + 1 - 4
= 3 - 3
= 0
====================================
i think the answer should b 0
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