Question

4 Sin 30 + tan 48.tan 42-3 tan 45​

Answer 1

Answer: sin30=½

tan45=1

so

4(½) + 3(1)

2+3

=5

Step-by-step explanation:

Answer 2

$\displaystyle \sf{ 4 \: sin {30}^{ \circ} + tan {48}^{ \circ}tan{42}^{ \circ} - 3 \: tan{45}^{ \circ}} = 0$

Given :

$\displaystyle \sf{ 4 \: sin {30}^{ \circ} + \: tan {48}^{ \circ}tan{42}^{ \circ} - 3 \: tan{45}^{ \circ}}$

To find :

The value of the expression

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

$\displaystyle \sf{ 4 \: sin {30}^{ \circ} +\: tan {48}^{ \circ}tan{42}^{ \circ} - 3 \: tan{45}^{ \circ}}$

Step 2 of 2 :

Find the value of the expression

$\displaystyle \sf{ 4 \: sin {30}^{ \circ} + tan {48}^{ \circ}tan{42}^{ \circ} - 3 \: tan{45}^{ \circ}}$

$\displaystyle \sf{ = 4 \: sin {30}^{ \circ} + tan {48}^{ \circ}tan({90}^{ \circ} - {48}^{ \circ}) - 3 \: tan{45}^{ \circ}}$

$\displaystyle \sf{ = 4 \: sin {30}^{ \circ} + tan {48}^{ \circ} \: cot {48}^{ \circ} - 3 \: tan{45}^{ \circ}}$

$\displaystyle \sf{ = 4 \times \frac{1}{2} + tan {48}^{ \circ} \times \frac{1}{tan {48}^{ \circ}} - 3 \: \times 1}$

$\displaystyle \sf{ = 2 + 1 - 3}$

$\displaystyle \sf{ = 0}$