4 (sin^4 30+cos^2 60)_3 (cos^2 45_2sin^2 45)
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Heya,
Sin 30° = 1/2
cos 60° = 1/2
cos 45° = 1/√2
sin 45° = 1/√2
Given=> 4( sin⁴30° + cos²60°) - 3(cos²45° - 2sin²45°)
=> 4[(1/2)⁴ + (1/2)²] - 3[(1/√2)²- 2(1/√2)²]
=> 4(1/16 + 1/4) - 3(1/2 - 2/2)
=> 4(5/16) - 3(-1/2)
=> 5/4 + 3/2
=> (5 + 6)/4
=> 11/4. ...... Answer
Hope this helps....:)
Sin 30° = 1/2
cos 60° = 1/2
cos 45° = 1/√2
sin 45° = 1/√2
Given=> 4( sin⁴30° + cos²60°) - 3(cos²45° - 2sin²45°)
=> 4[(1/2)⁴ + (1/2)²] - 3[(1/√2)²- 2(1/√2)²]
=> 4(1/16 + 1/4) - 3(1/2 - 2/2)
=> 4(5/16) - 3(-1/2)
=> 5/4 + 3/2
=> (5 + 6)/4
=> 11/4. ...... Answer
Hope this helps....:)
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