4(sin^4 30+cos^2 60)-3(cos^2 45-sin^2 90)-sin^2 60.Please answer this.
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=4[(1/2)^4+(1/2)^2]-3[1/√2)^2-1^2)-(√3/2)^2
=4(1/16+1/4)-(1/2-1)-3/4
=4/16+4/4-3(1-2/2)-3/4
=1/4+1-3(-1/2)-3/4
=5+6-3/4
=8/4
=2
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