4(sin 45° + cos+ 45°)- 2(tan- 30+ cot 30°) +cosec²45°
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Answer:
tan260∘+4cos245∘+3sec230∘+5cos290∘
tan260∘+4cos245∘+3sec230∘+5cos290∘=2+2−(3)2(3)2+4(21)2+3(32)2+5(0)
tan260∘+4cos245∘+3sec230∘+5cos290∘=2+2−(3)2(3)2+4(21)2+3(32)2+5(0)=2+2−33+4(21)+3(34)
tan260∘+4cos245∘+3sec230∘+5cos290∘=2+2−(3)2(3)2+4(21)2+3(32)2+5(0)=2+2−33+4(21)+3(34)=3+4(21)+3(34)
tan260∘+4cos245∘+3sec230∘+5cos290∘=2+2−(3)2(3)2+4(21)2+3(32)2+5(0)=2+2−33+4(21)+3(34)=3+4(21)+3(34)=3+2+4
tan260∘+4cos245∘+3sec230∘+5cos290∘=2+2−(3)2(3)2+4(21)2+3(32)2+5(0)=2+2−33+4(21)+3(34)=3+4(21)+3(34)=3+2+4=9
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9 is the right answer
hope it help you a lot
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