Math, asked by soodjhanvi954, 1 month ago

4(sin 45° + cos+ 45°)- 2(tan- 30+ cot 30°) +cosec²45°
please answer fast​

Answers

Answered by ranjeetcarpet
0

Answer:

tan260∘+4cos245∘+3sec230∘+5cos290∘

tan260∘+4cos245∘+3sec230∘+5cos290∘=2+2−(3)2(3)2+4(21)2+3(32)2+5(0)

tan260∘+4cos245∘+3sec230∘+5cos290∘=2+2−(3)2(3)2+4(21)2+3(32)2+5(0)=2+2−33+4(21)+3(34)

tan260∘+4cos245∘+3sec230∘+5cos290∘=2+2−(3)2(3)2+4(21)2+3(32)2+5(0)=2+2−33+4(21)+3(34)=3+4(21)+3(34)

tan260∘+4cos245∘+3sec230∘+5cos290∘=2+2−(3)2(3)2+4(21)2+3(32)2+5(0)=2+2−33+4(21)+3(34)=3+4(21)+3(34)=3+2+4

tan260∘+4cos245∘+3sec230∘+5cos290∘=2+2−(3)2(3)2+4(21)2+3(32)2+5(0)=2+2−33+4(21)+3(34)=3+4(21)+3(34)=3+2+4=9

Step-by-step explanation:

PLEASE MARK AS BRANILST AND LIKE

Answered by gaurianushka987
1

9 is the right answer

hope it help you a lot

Similar questions