Question

what is the value of k, if the value of Dy for the equation 2x + y = 19 and 3x + ky = 11 is -35​

Answer 1

Step-by-step explanation:

I hope this picture you can help

Please briliyant marks

Answer 2

Concept:

The determinant is defined as a scalar value which is associated with the square matrix.

For equation:

$ax+by=c\\px+qy=s$

then,

$D=\left[\begin{array}{ccc}a&b\\p&q\end{array}\right]$

Given that:

2 equations 2x + y = 19 and 3x + ky = 11 are given.

Value of

D=-35               ---------(1)

To find:

Value of k.

Solution:

The 2 equations are

$2x+y=19\\3x+ky=11$

Then,

$D=\left[\begin{array}{ccc}2&1\\3&k\end{array}\right]$

⇒$D=2(k)-3$

From equation (1)

$2k-3=-35$

⇒$2k=-38$

⇒$k=\frac{-38}{2} =-19$

Therefore, the value of k is -19.