Question

4. Sodium carbonate reacts with dilute hydrochloric acid as follows:
Na co + 2HCl _ 2NaCl + H2O +
H2O + CO21
What mass of Naco, is required to neutralize 200 ml of 0.6 M HCl completely? [Atomic mass of Na - 23; C-12; 0-16 g/mol]​

Answer 1

Answer:

The reaction is as: Na 2 CO 3+2HCl→2NaCl+H 2 O+CO 2

Let weight of Na 2

CO

3

be M.

In this reaction, 1 mole of sodium carbonate reacts with 2 moles of hydrochloric acid or 2 equivalents of HCl.

∴

2

1

mole of Na

2

CO

3

is equivalent to the equivalent mass of Na

2

CO

3

.

Thus, the equivalent mass of sodium carbonate is

2

M

.