4. Solve 2x + 3y = 12 and 3x + 2y = 13
in the method of substitution.
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Answer:
2x+3y=12..............(1)
3x+2y=13.
3x=13-2y
x=13-2y/3.............(2)
Substituting the value of x in equation (1),
2(13-2y/3) +3y=12
26-4y/3+3y=12
26-4y+9y/3=12
26-4y+9y=36
26+5y=36
5y=36-26
5y=10
y=10/5
y=2
Substituting the value of y in equation (1) we get,
2x+3(2) =12.......... (1)
2x+6=12
2x=12-6
2x=6
x=6/2
x=3
Therefore,
The solution of the given equation is (3, 2).
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