Question

In a bag, there are a certain number of toy-blocks with alphabets A, B, C and D written on them. The ratio of blocks A:B:C:D is in the ratio 4:7:3:1. If the number of ‘A’ blocks is 50 more than the number of ‘C’ blocks, what is the number of ‘B’ blocks?

Answer 1

Answer:

350 Blocks

Step-by-step explanation:

A: 4/15

B: 7/15

C: 3/15=1/5

D: 1/15

A-D= 1/15 = 50 more  

7*50= 350 Blocks

Answer 2

GIVEN :

• RATIO OF A , B , C & D = 4 : 7 : 3 : 1

• NUMBER OF A BLOCKS IS 50 more than the C BLOCKS

SOLUTION :

LET THE NUMBER OF A- BLOCKS BE 4x , B- BLOCKS BE 7x , C - BLOCKS BE 3x & D - BLOCKS BE x

IF NUMBER OF C BLOCKS IS 3x THEN NUMBER OF A - BLOCKS IS 3x + 50 [ ∵ GIVEN]

BUT NUMBER OF A - BLOCKS = 4x

=> 4x = 3x + 50

=> x = 50

THEN ,

NUMBER OF A -BLOCKS = 4x = 4(50) = 200

NUMBER OF B -BLOCKS = 7x = 7(50) = 350

NUMBER OF C- BLOCKS = 3x = 3(50) = 150

NUMBER OF D- BLOCKS = x = 50

∴ NUMBER OF B - BLOCKS = 350

HOPE IT HELPS !!!!