Question

4. Sudhakar borrows * 22500 at 10% per annum, compounded annually. If he repays ? 11250
at the end of first year and 12550 at the end of the second year, find the amount of loan
outstanding against him at the end of the third year.

Answer 1

Answer:

amount=P*R*T/100

22500*10*3/100=6750

22500+6750=29250

he paid at first year is 11250.

second year is12550

so, 12550+11250=23800

now the amount left at the end of third year,

29250-23800=5450

answer is 5450.

hope it helps