4) Sum of the ages of father and son is 68. After 8 years
father will be thrice as old as son. The present age
(in years) of the son is
A) 18
B) 16
C) 15
D) 13
On
is 60% more than that of B's income, then
Answers
Question :- Sum of the ages of father and son is 68. After 8 years father will be thrice as old as son. The present age
(in years) of the son is :-
A) 18
B) 16
C) 15
D) 13
Answer :-
Let us assume that, Present age of son is x years.
so,
→ Father's age = (68 - x) years.
now,
→ After 8 years son will be = (x + 8) years old.
→ After 8 years father will be = (68 - x) + 8 = (76 - x) years old.
A/q,
→ Father = 3 * son
→ (76 - x) = 3(x + 8)
→ 76 - x = 3x + 24
→ 76 - 24 = 3x + x
→ 4x = 52
→ x = 13 years. (D) (Ans.)
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Given:
Sum of ages of father and son = 68
After 8 years the age of father will be thrice as old as son.
To find: The present age (in years) of the son.
Solution:
Let the present age of father be x and that of son be y.
x + y = 68 …………. (1)
After 8 years:
age of father = x + 8
age of son = y + 8
A.T.Q:
(x + 8) = 3(y + 8)
x + 8 = 3y + 24
x = 3y + 24 - 8
x = 3y + 16 ………..(2)
Put this value of x in equation 1:
x + y = 68
3y + 16 + y = 68
4y + 16 = 68
4y = 68 - 16
4y = 52
y = 52/4
y = 13 years
Present age of son = 13 years
Hence, the present age of the son is 13 years.
Option (D) 13 is correct.
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