Question

4) Sum of the ages of father and son is 68. After 8 years
father will be thrice as old as son. The present age
(in years) of the son is
A) 18
B) 16
C) 15
D) 13
On
is 60% more than that of B's income, then​

Answer 1

Question :- Sum of the ages of father and son is 68. After 8 years father will be thrice as old as son. The present age

(in years) of the son is :-

A) 18

B) 16

C) 15

D) 13

Answer :-

Let us assume that, Present age of son is x years.

so,

→ Father's age = (68 - x) years.

now,

→ After 8 years son will be = (x + 8) years old.

→ After 8 years father will be = (68 - x) + 8 = (76 - x) years old.

A/q,

→ Father = 3 * son

→ (76 - x) = 3(x + 8)

→ 76 - x = 3x + 24

→ 76 - 24 = 3x + x

→ 4x = 52

→ x = 13 years. (D) (Ans.)

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Answer 2

Given:

Sum of ages of father and son = 68  

After 8 years the age of father will be thrice as old as son.

To find: The present age (in years) of the son.

 

Solution:

Let the present age of father be x and that of son be y.

x + y = 68 …………. (1)

After 8 years:

age of father = x + 8

age of son = y + 8

A.T.Q:

(x + 8) = 3(y + 8)

x + 8 = 3y + 24

x = 3y + 24 - 8

x = 3y + 16 ………..(2)

Put this value of x  in equation 1:

x + y = 68

3y + 16 + y = 68

4y + 16 = 68

4y = 68 - 16

4y = 52

y = 52/4

y = 13 years  

Present age of son = 13 years

Hence, the present age of the son is 13 years.  

Option (D) 13 is correct.  

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