Question

4. Sum of the three numbers is 16. The second number is 2 less than the first number and
the third is four times the first number. Find the three numbers.​

Answer 1

Answer:

let the first no be x

second no= x-2

third no= 4x+x-2+x=16

4x+x+x=16+2

4x+x+x=18

6x=18

x=18÷6

x=3

second no.=x-2

= 3-2

=1

third no.= 4x

= 4×3

=12

the three numbers are 3,1,12

Answer 2

The three numbers are 3 , 1 , 12.

• Let the three numbers be x,y and z.
• Sum of numbers is 16.

x+y+z = 16    ......(Equation 1)

• Second number is 2 less than first number.

y = x- 2     .......(Equation 2)

• Third number is 4 times the first number.

z = 4x       ......(Equation 3)

• Substituting the value of y and z in equation 1 from equation 2 and 3

x + (x-2) +4x =16

6x = 18

x = 3

• Substituting the value of x in equation 2 and 3 to find y and z respectively.
• y = 3 -2 = 1
• z = 4x = 4(3) = 12