Question

divide a rope of length 560 cm into 2 parts such that twice the length of the smaller part is equal to 1/3 of the larger part then find the length of the larger part​

Answer 1

Step-by-step explanation:

Let the two parts of the rope be x and y, such that x > y.

$\therefore x + y = 560....(1)$

According to the given condition:

Twice the length of the smaller part is equal to 1/3 of the larger part.

$\therefore 2y = \frac{1 }{3} x\\</p><p>\therefore y = \frac{1 }{6} x....(2)$

From equations (1) & (2), we find:

$x + \frac{1 }{6} x=560\\</p><p>\therefore \frac{6x+x }{6}=560\\</p><p>\therefore \frac{7x}{6}=560\\</p><p>\therefore x= \frac{6}{7} \times 560\\</p><p>\therefore x= 6 \times 80\\</p><p>\huge\boxed {\purple{\therefore x= 480} }$