Math, asked by alkajindal1974pagluw, 1 year ago

4. Suppose you're in a hallway lined with 100 closed lockers.
You begin by opening every locker. Then you close every second locker.
Then you go to every third locker and open it (if it's
closed) or close it (if it's open). Let's call this action
toggling a locker. Continue toggling every nth locker
on pass number n. After 100 passes, where you
toggle only locker #100, how many lockers are open?


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Answers

Answered by sawakkincsem
8

Answer:

10 lockers

Step-by-step explanation:

This problem is based on the factors of the locker number.

The only way a locker could be left open is if it is toggled an odd number of times. The only numbers with an odd number of factors are the perfect

squares. Thus, the perfect squares are left open. Each of these numbers are perfect squares.

Example

Locker number 36 is toggled on pass number 1, 6, and 36 (three toggles): open-closed-open.

Locker numbers which are open are  1, 4, 9, 16, 25, 36, 49, 64, 81, and 100. We can clearly see that each of the above  locker numbers are perfect squares.

Answered by adamyachaturvedi
1

Answer:

Step-by-step explanation:

Answer: 10 lockers are left open:  

Lockers #1, 4, 9, 16, 25, 36, 49, 64, 81, and 100.  

Each of these numbers are perfect squares. This problem is based on the factors of the locker number.  

Each locker is toggled by each factor; for example, locker #40 is toggled on pass number 1, 2, 4, 5, 8, 10, 20, and 40. That's eight toggles: open-closed-open-closed-open-closed-open-closed.

The only way a locker could be left open is if it is toggled an odd number of times. The only numbers with an odd number of factors are the perfect  

squares. Thus, the perfect squares are left open.  

For example, locker #25 is toggled on pass number 1, 5, and 25 (three toggles): open-closed-open.

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