4 th term of an ap is eqval to 3 times it's first term and 7 term exceeds with twice the 3rd by 1 find the term of common difference
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1
Answer:
Step-by-step explanation:
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Answer:-2
Step-by-step explanation:
First,a+3d=3a,Eq1
And eq2 is a+6d+1=2(a+2d)
a+6d+1=2a+4d
a-2d-1=0
a=2d+1
SubstItute, a=2d+1in Eq 1
a+3d=3a
2a-3d=0
2(2d+1)-3d=0
4d+2-3d=0
d=-2
So the common difference is d=-2
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