Question

4. The age of a man is twice the sum of the ages of his two children. After 20 years, his age will be equal to the sum of the ages of his children at that time. Find the present age of the man.why
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Answer 1

ANSWER:

40 years

STEP-BY-STEP EXPLANATION:

Given that the age of a man is twice the sum of the ages of his two children.

Let's say the age of man be "x" years and age of his two children be "y" years.

As per given condition,

→ x = 2y ------------- (eq 1)

After 20 years, his age will be equal to the sum of the ages of his children at that time.

After 20 years:

• Age of man = (x + 20) years
• Age of two children = (y + 20 + 20) = (y + 40) years

As per given condition,

→ x + 20 = y + 40

→ x - y = 40 - 20

→ x - y = 20 ------------ (eq 2)

Substitute value of x in (eq 2)

→ 2y - y = 20

→ y = 20

Substitute value of y in (eq 1)

→ x = 2(20)

→ x = 40

Therefore, the present age of man is 40 years.