Question

A month is selected at random in a year. Find the
probability that it is either January or June. .

Answer 1

Step-by-step explanation:

n(S) =12

Let A be an event of getting january

n(A) = 1

P(A) =n(A) /n(S) =1/12

Let B be an event of getting june

n(B) =1

P(B) =n(B) /n(S) = 1/12

P(A intersection B) = (

they are mutually exclusive events

P(AUB) = P(A) +P(B)

Apply this formula

Hope this is helpful to you.