Question

4. The angle of elevation of the top of a tower at a point 50 m away
from the foot of tower is 60°. Find the height of the tower.​

Answer 1

Answer:

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Answer 2

Answer:

━☞Hence The height of tower is 86.6 m

Step-by-step explanation:

━☞Given:

• The angle of elevation of the top of a tower at a point 50 m away
• from the foot of tower is 60°.

━☞To Find:

height of the tower.

━☞Solution:

Distance between the point and the foot of tower = Base = 50 m

Angle of elevation = 60°

We are supposed to find the height of tower i.e. Perpendicular

$so \: \tan0 \: = \frac{perpendicular}{base}$

$\tan60 {}^{.} = \frac{height}{50}$

$\sqrt{3} \times 50 = height$

$86.6 =Height$

━☞Hence The height of tower is 86.6 m