Question

4. The angular momentum of electron in 'd'
orbital is equal to
(2015)
1) 2V3h 2) 0 h 3) V6h 4) V2h​

Answer 1

Answer:

Option 3 is correct

Explanation:

Value of l for d orbital = 2

hence, required angular momentum

$= \sqrt{l(l + 1)} \frac{h}{2\pi} \\ = \sqrt{2(2 + 1)} \frac{h}{2\pi} \\ = \sqrt{6} \frac{h}{2\pi}$

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