Math, asked by tasneem139, 10 months ago



4. The attendance at a party consisted of 35 men, a number of women and some children. The
number of women was one and a half times that of the children present.
a) If there were a total of 65 participants, how many women attended the party?
(2mks)

b) During the party, each child took one bottle of soda, the men took two bottles
each while some women took two and others three. Given that five crates each
containing 24 bottles of soda were consumed, how many women took two bottles
of soda?
(6mks)​

Answers

Answered by Anonymous
4

Answer:

1.TOTAL PARTICIPANTS =65

MEN=35

SO NO OF WOMEN + CHILDREN =65_35=30

GIVEN

no of women were one half times that of children present so

NO OF CHILDREN =20

NO OF WOMEN =10

2.each child took one bottle of soda so

No OF SODA CONSUMED = 20

each men took two bottles of soda so

NO OF SODA CONSUMED = 35×2=70

TOTAL NUMBER OF SODA CONSUMED BY CHILDREN AND MEN =90

GIVEN THAT

five crates each containing 24 bottles of soda were consumed so

TOTAL NUMBER OF SODA CONSUMED = 24×5=120

TOTAL NUMBER OF SODA CONSUMED BY WOMEN =120_90=30

TOTAL NUMBER OF WOMEN WHO TOOK TWO BOTTLES OF SODA =......

iam not getting this

iam sorry I give up

Answered by gajindrathakur15
0
Sorry can’t help I cannot understand your question
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