Question

4.
The centre of the circle having end points of its one diameter as (-4, 2)
and (4, -3) is
(A)
(B)
(2, -1)
(0, -1)
(0,
1
2
(C)
| сол
(D)
(4, -
2​

Answer 1

$End \: points \: of \: a \: Diameter \: of \: a \\ circle \: (-4,2) = (x_{1} , y_{1})\\and \: (4,-3) = (x_{2} , y_{2})$

$\red{ Centre \: of \: the \: circle }\\=Mid point \: of \: the \: Diameter \\= \Big( \frac{x_{1}+x_{2}}{2} , \frac{</p><p>y_{1}+y_{2}}{2}\Big) \\= \Big( \frac{-4+4}{2} , \frac{2-3}{2}\Big) \\=\Big( 0 , \frac{-1}{2}\Big)$

Therefore.,

$\red{ Centre \: of \: the \: circle }$

$\green { = \Big( 0 , \frac{-1}{2}\Big)}$

•••♪