Question

4.
The coordinate of a moving particle at any time 't' are given by x = ct2 and y = bt2. The velocity of
particle at time t'is given by
(a) 2t(a - b)
(b) vc2 + b2 (c) 2tVc2 + b2 (d) 2tVc2 – 52​

Answer 1

HERE , I DENOTE SI(SIMPLE INTEREST) , R(RATE) , T(TIME PERIOD) , P(PRINCIPAL).

HERE(IN THE PROBLEM) THE MEANING OF 'SUM' IS PRINCIPAL.

'SI' IS GIVEN , 'R' IS GIVEN , 'T' IS GIVEN.

WE HAVE TO FIND 'P'.

p = \frac{si \: \times 100}{r \: \times \: t}p=

r×t

si×100

si is rs.112.50 , r is 10% , t is 1 1/2 = (3/2) years

p \: = \: \frac{112.50 \: \times 100}{10 \: \times \frac{3}{2} }p=

10×

2

3

112.50×100

p = \frac{ 11250×100×2 }{10 \times 3 \times 100}p=

10×3×100

11250×100×2

p \: = \frac{11250 \times 2}{10 \times 3}p=

10×3

11250×2

p \: = \frac{11250}{3 \times 5}p=

3×5

11250

p \: = \frac{11250}{15}p=

15

11250

p \: = rs.750p=rs.750

so your sum is rs.750

ANS = THE SUM IS RS.750.

HOPE IT HELPS YOU!!!!