4. The daily cost of milk (in Rs) supplied to 25 houses in a locality are given below : If one house is chosen at random, find the probability that
(a) the milk bill of the house lies between Rs 60 and Rs 80.
(b) house is paying at the most Rs 69, for the milk bill.
(c) the milk bill of the house is below Rs 50.
(d) the milk bill of the house is less than Rs 40.
its urgent pls answer
Answers
Answer:
number of houses where milk is supplied = 25.
then,
(a)
total = 8
Probabilities of milk bill lies between Rs 60 and Rs 80 is :
P(E) = number of favourable outcomes/total no of
outcomes.
P(E) = 8/25.
(b) house is paying at the most Rs 69,for milk bill
probability of houses paying at most Rs 69,for milk bill is :
P(E) = no. of favourable outcomes/ total no. of
outcomes
P(E) = 3/25
(c) the milk bill of houses below Rs 50
milk bill of houses below Rs 50 are, 4
Probability of milk bill of houses below Rs 50 are :
P(E)=no of favourable outcomes
_____________________
total number of outcomes
P (E) = 4/25
(d) milk of house less than Rs 40 are equal to 0
Probability of milk bill of houses less than Rs 40 are :
P (E) = no of favourable outcomes
_____________________
total number of outcomes
P ( E) = 0/25
P(E) = 0
THIS IS THE CORRECT ANSWER OF YOUR QUESTION.
Answer:
Step-by-step explanation: