Question

4. The diagonals of a rectangle ABCD intersect at O. If angleBOC = 44, find angleOAD.
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Answer 1

Answer:

hi mate,

Angle DOA=angle BOC(vertically opposite angles)

Angle DOA=44°

We know that in a rhombus diagonals are equal and bisect each other.

So, AC=BD

AO=OD(diagonals bisect each other in a rectangle)

So, angle OAD=angle ODA(angles opposite to equal sides are equal)

So, ∆AOD is an isosceles ∆ .

Using angle sum property in ∆AOD

angle DOA+angle ODA+angle OAD=180°

44°+angle OAD+angle OAD =180°

44°+2×angle OAD=180°

2×angle OAD=180°-44°

2×angle OAD=136

angle OAD=136/2

angle OAD=68°

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Step-by-step explanation:

Answer 2

Answer:

angle AOD bhi 44 hi hoga

Step-by-step explanation:

because

angle BOC=angle OAD. (vertical opposite angle)