Question

4. The distance between two stations A and B is 200 km. Two trains start at the same time from
A and B in the opposite directions towards each other. After 2 hours, the distance between
them is 50 km. If the speed of one train is 5 km/h more than the other train, find their speeds.​

Answer 1

Step-by-step explanation:

Let X be the speed of the slower train in km/hr

speed of other one will be (x+5) km/hr.

Now,

distance travelled by slower train in 2 hrs= speed × time

= x×2

= 2x

distance travelled by Faster train in 2 hrs= 2*(x+5).

Now ,

2x+ 2(x+5) +50=200

→x= 35km/hr see picture

speed of second train = 30+5 = 35km/hr

Answer 2

$\huge \bold { \red{ \underline{Solution}}}$

Let the speed of the train travel slower be (x km/h)

A.T.Q speed of faster train be (x + 5 km/h)

Dis tance traveled by slower train in 2 hours.

${ \sf{Speed = \frac{ Speed = Distance}{Time}}}$

= Distance = Speed × Time

= Distance = (x)*2

= Distance = 2 × km

Distance traveled by faster train

= Distance = Speed × time

= Distance = (x + 5) × 2

= Distance = (2x + 10) km

Now, total distance was 200 and the had traveled 150 km after 2 hour.

So, 2x + 2x + 10 = 150

= 4x + 10 = 150

= 4x = 150 - 10 = 140

$\sf{ x = \frac{140}{4} = 35 \: km/h}$

Now, Speed of slower train is 35 km/h

Speed of faster train is (35 + 5) = 40 km/h