Question

Q.24 In angle ABC, angle A = yº, angle B = (y – 9)º, angle C = xº. Also angle B – angle C = 48º, find the

three angles...Please please help , I will mark brainiliest​

Answer 1

Step-by-step explanation:

In a triangle ABC :

angle A + angle B + angle C = 180

--------------(angle sum property of triangle)

• angle C - angle B = 9

y - (3x-2) = 9

y = 9+(3x-2)

y = 7+3x

•x + (3x-2) + y = 180

x + (3x-2) + (7+3x) = 180

x + 3x + 3x -2+7 = 180

7x = 175

x = 25°

• y = 7 + 3×25

y = 82°

The respective angles of the triangle ABC are ;

Angle A = x = 25°

Angle B = 3x-2 = 73°

Angle C = y = 82°

hope this helped,

Answer 2

Answer:

Step-by-step explanation:

∠A  = y°

∠B = (y-9)°

∠C = x°

∠B - ∠C = 48°

∠C = ∠B - 48° = (y-9)° - 48°

In a triangle ∠A + ∠B + ∠C = 180°

y° + (y-9)° + (y-9)° - 48° = 180

3y° - 66° = 180°

3y° = 180° + 66°

y° = (246/3)° = 82°