Question

4. The distance covered by a motor bike at various
instances of time are as follows.
DISTANCE (m) 0
4 8 12 16 20 24
TIME (sec)
0 2. 4 6 8 10 12​

Answer 1

Let a be the first term and d be the common difference

T10  = a + 9d,  T15  =  a + 14d

10T10 = 15T15

⇒ 10(a + 9) d = 15(a + 14d)

⇒ 2(a + 9) d = 3(a + 14d)

⇒ a + 24d = 0

∴ T25  = 0