Question

4) The HCF of two numbers is 12
and their product is 2160 . Find their
L.C.M?​

Answer 1

Answer:

HCF×LCM=PRODUCT OF GIVEN NUMBER SO

12×LCM=2160

LCM=2160/12

LCM=180

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Answer 2

180

Step-by-step explanation:

let the two numbers be 12x and 12 y

such that

12x × 12 y = 2160

or xy= 2160÷ 144

or xy= 15 .

LCM= HCF × remaining

= 12 × x × y [ X is remainder of 12x and y

is remainder of 12 y]

= 12 × 15

= 180