Question

4) The magnitude of vector product of
two unit vectors making an angle
of 60° with each other is​

Answer 1

Answer:

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Answer 2

Answer:

2

Explanation:

The magnitude of vector product of two unit vectors makes an angle of 60° We have to find their product:

Let the vectors Set a and Set b

Set a=(2,0) and

$Set\ b=(2\times cos60^o, 2\times sin60^o)$

negative vector has opposite direction but same magnitude.

$a-b = (2-2\timescos(60^o),0-2\timessin(60^o)) \\\\a-b= (2-1,-2\times \dfrac{\sqrt3}{2} = (1,-\sqrt3)$

$||a-b||= \sqrt{(a-b)^2} = \sqrt{1^2+(\sqrt3^2)} =\sqrt{4}\\||a-b||= 2$