Question

4.The mean of the following frequency distribution is 24.Find the value of P
Class
0-10
10-20
20-30
30-40
40-50
frequency 15
20
35
P
10

cond the sum of the​

Answer 1

Class Interval Frequency f

i

Mid-Value x

i

f

i

x

i

0−10 3 5 15

10−20 4 15 60

20−30 p 25 25p

30−40 3 35 105

40−50 2 45 90

∑f

i

=12+p ∑f

i

x

i

=270+25p

Mean =

∑f

i

∑f

i

x

i

Mean =24 (given)

⇒24=

(12+p)

(270+25p)

⇒24(12+p)=270+25p

or p=18

Answer 2

Answer:

(15+20+35+p+10)/5=24

80+p=120

p=120-80=40