Question

(4) The measure of angles of a triangle are x®,(x-20)*,( X-40).
Find the measure of each angle.​

Answer 1

Answer:

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Step-by-step explanation:

Let us suppose the angles ∠P, ∠Q, ∠R of a ∆PQR be x°, (x - 20)°, (x - 40)° respectively.

∠P + ∠Q + ∠R = 180∘   (Angle sum property)

⇒ x∘ + (x - 20)° + (x - 40)° = 180°

⇒ 3x - 60 = 180  

⇒ 3x = 240

⇒ x ​= 80

Therefore,

∠P = 80∘°

∠R = (80 - 20)°  = 60°

∠R = (80 - 40)°  = 40°

Hence, the measure of each angle is 80∘, 60∘ and 40∘respectively.

Answer 2

We know, sum of three angles in traingle =180°

so, x+x-20+x-40 =180

or, 3x-60 =180

or, 3x =180+60

or, 3x =240

or, x= 240/3 = 80

Now, x-20 =80-20 =60

x-40 =80-40 =40

Thus, three angles are 80°, 60° and 40°.