Physics, asked by siddharthdora01, 4 months ago

4. The position of a body at different
times are given as x = 5 + 3 t^2 m.

Calculate the velocity at t=1 sec and
t=4 sec. What is the average velocity
between t=3 sec and t= 5 sec.​

Answers

Answered by luckythegamer809
1

Explanation:

The distance travelled by body in time interval t = 0 to t = 3 s is. ... Given,. x=t2−4t+6. So, the change in velocity is: ... So distance traveled from t=2s to t=3s ... 4+1=5m.

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