Chemistry, asked by preetrank24, 9 months ago

(4) The potential of the following cell is 0-586 V at 298 K
temperature. Calculate the ionic product of water (K)
Pt1 HX) (1 bar) KOH (0-1 M) | HCI (0-001M)
H2(g) (1 bar)

Answers

Answered by parasmani89

1

Answer:

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Answered by haleemninja

1

Answer:

what

Explanation:

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