Math, asked by akshanshmehrotra, 1 month ago

4. The printed price of a painting is * 17,000. A dealer allows two successive discounts of
18% and 15%. Find the price which a customer has to pay for the painting.​

Answers

Answered by MasterDhruva
1

How to do :-

Here, we are given with the printed price of a painting and two successive discounts allowed for the costumer to buy that painting. We are asked to find the selling price of that painting or the cost which is been paid by the customer to buy that painting. Here, we should solve the problem two times in which firstly we'll use the cost price of that painting and the first discount allowed and then second time, we use the answer obtained by solving by first time and the second discount allowed to buy the painting. This answer will be the selling price or the cost paid by the costumer to buy the painting. We should solve it two times as we are given with two successive discounts for the particular painting done. So, let's solve!!

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Solution :-

{\sf \leadsto 18 \% \: of \: 17000}

Write the percentage as fraction and 'of' as multiplication sign.

{\sf \leadsto \dfrac{18}{100} \times 17000}

Write the fraction in lowest form by cancellation method.

{\sf \leadsto \cancel \dfrac{18}{100} \times 17000 = \dfrac{9}{50} \times 17000}

Multiply the remaining numbers.

{\sf \leadsto \dfrac{9 \times 17000}{50} = \dfrac{153000}{50}}

Write the fraction in lowest form by cancellation method.

{\sf \leadsto \cancel \dfrac{153000}{50} = 3060}

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Now, let's find the selling price of the painting.

Selling price of the painting :-

{\sf \leadsto 15 \% \: of \: 3060}

Write the percentage as fraction and 'of' as multiplication sign.

{\sf \leadsto \dfrac{15}{100} \times 3060}

Write the fraction in lowest form by cancellation method.

{\sf \leadsto \cancel \dfrac{15}{100} \times 3050 = \dfrac{3}{20} \times 3050}

Multiply the remaining numbers.

{\sf \leadsto \dfrac{3 \times 3050}{20} = \dfrac{9150}{20}}

Write the fraction in lowest form by cancellation method.

{\sf \leadsto \cancel \dfrac{9150}{20} = 457.5}

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{\red{\underline{\boxed{\bf So, \: the \: cost \: paid \: by \: customer \: is \: 457.5.}}}}

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