Question

4. The radius of a sphere is (5.3 +0.1) cm. The
percentage error in its volume is
0.1
x 100
5.3
0.1
(2) 3xx100
5.3
3 0.1
(3) = x100
2 5.3
0.1
(4) 6x-x100
0.3​

Answer 1

Answer:

Your Answer: 5.66 ℅

Given: r=5.3±0.1 cm

Given: r=5.3±0.1 cmSo, Δr=0.1cm and r=5.3cm

Given: r=5.3±0.1 cmSo, Δr=0.1cm and r=5.3cmPercentage error in volume=

Given: r=5.3±0.1 cmSo, Δr=0.1cm and r=5.3cmPercentage error in volume= V

Given: r=5.3±0.1 cmSo, Δr=0.1cm and r=5.3cmPercentage error in volume= VΔV

Given: r=5.3±0.1 cmSo, Δr=0.1cm and r=5.3cmPercentage error in volume= VΔV

Given: r=5.3±0.1 cmSo, Δr=0.1cm and r=5.3cmPercentage error in volume= VΔV ×100%=

Given: r=5.3±0.1 cmSo, Δr=0.1cm and r=5.3cmPercentage error in volume= VΔV ×100%= 5.3 cm

Given: r=5.3±0.1 cmSo, Δr=0.1cm and r=5.3cmPercentage error in volume= VΔV ×100%= 5.3 cm3×0.1 cm

Given: r=5.3±0.1 cmSo, Δr=0.1cm and r=5.3cmPercentage error in volume= VΔV ×100%= 5.3 cm3×0.1 cm

Given: r=5.3±0.1 cmSo, Δr=0.1cm and r=5.3cmPercentage error in volume= VΔV ×100%= 5.3 cm3×0.1 cm ×100%=5.66%

Explanation:

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