4) The sum of the zeros of the polynomial px2 + qx + m is
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Step-by-step explanation:
Given polynomial is px²+qx+m
on comparing with ax²+bx+c
we have,a=p;b=q;c=m
Sum of zeroes=-b/a=-q/p
The sum of the zeroes=-q/p
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Answer:
-q/p is the answer for your question
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