Question

4. The values of X and Y when a point lies on the linear equation 2x-3y=12
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Answer 1

Step-by-step explanation:

first of all

2x-3y=12 eq1

x=3y+12/2

x=3/2y+6 eq 2

put x=3/2y+6 in eq 1

2(3/2y+6)-3y=12

6/2y+12-3y=12

3/y+12-3y=12

3/y-3y+12=12

3-3y^2/y+12=12

3-3y^2/y=12-12

3-3y^2/y=0

3-3y^2=0

by taking common

3(1-y^2)=0

1-y^2=0

1=y^2

by taking square roots on both sides

y=1

put y=1 in eq 2

x=3/2(1)+6

x=3/2+6

x=3+12/2

x=15/2