Question

4. Three equal resistance each of 10 ohm are connected
as shown. The maximum power which can be
consumed by each is 20 W. What is the maximum
power that can be consumed by the combination
(1) 5 W
(2) 15 W
(3) 30 W
(4) 60 W​

Answer 1

Answer:

Option C means Option 3rd- 30 W

Answer 2

Concept Introduction:-

An electrical circuit's resistance is how it resists current flow.

Given Information:-

We have been given that Three equal resistance each of $10$ ohm are connected as shown and the maximum power which can be consumed by each is $20$ W.

To Find:-

We have to find that the maximum power that can be consumed by the combination.

Solution:-

According to the problem

The Effective resistance of $2$ parallel resistors are

$R=R_{1}R_{2}/(R_{1}+R_{2})$

​​​​​​ $=100/20=5$

Then there is $2$ resistors of $5$ and $10$ in series,their effective resistance,

$R=R_{1}+R_{2}\\=5+10\\=15$

now we know

$p=I^{2} R$

From the equation we know

$p \propto R$

$10$ Ω is used  $20$ watt is consumed

so when $15$ Ω is used $\frac{20}{10} \times 15=30$

Final Answer:-

The maximum power can be consumed is $30$ W, the option C is correct.