Question

4. Two coins are tossed simultaneously 100 times, and we get
Two heads : 33, One head : 28, No head : 39
Find the probability of getting (i) at least one head (ii) at most one head.
plzz answer in brief
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Answer 1

Step-by-step explanation:

Given Two coins are tossed simultaneously 100 times, and we get Two heads : 33, One head : 28, No head : 39

Find the probability of getting (i) at least one head (ii) at most one head.

• So two coins are tossed simultaneously 100 times.
• Now total number of events will be 100
• Getting one head will be 28 times.
• So probability of getting one head = number of one head / Total number of events
•                                                      = 28 / 100
•                                                     = 7 / 25
• Probability of getting at most one head = number of favourable outcome / total number of outcomes.
•                                                    = 39 + 28 / 100 (since heads can be 0 and 1)
•                                                               = 67 / 100

Reference link will be

https://brainly.in/question/8501906

Answer 2

Answer:

67/100 will be the correct answer hope it helps you