Math, asked by mysticd, 5 months ago

4. Two cyclists start from the same point and ride in opposite directions. One cyclist
ride twice as fast as the other. In three hours, they are 72 miles apart. Find the rate
of each cyclist.​

Answers

Answered by amitnrw
4

Given : Two cyclists start from the same point and ride in opposite directions  

One cyclist  ride twice as fast as the other

In three hours, they are 72 miles apart

To Find : rate  of each cyclist.​

Solution:

Let say speed of one cyclist  =  A miles/hr

speed of other cyclist  =  2A miles/hr

Distance = Speed * time

Distance  covered in 3 hrs by 1st cyclist  =   A * 3 = 3A  miles

Distance  covered in 3 hrs by 2nd cyclist  =   2A * 3 = 6A  miles

Total Distance between Them = 3A + 6A = 9A miles

Total Distance = 72 miles

9A = 72

=> A = 8  

speed of one cyclist  =  8 miles/hr

speed of other cyclist  =  2*8 = 16  A miles/hr

rate  of each cyclist.​  = 8 miles per hr & 16 miles per hr

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Answered by tennetiraj86
5

Step-by-step explanation:

Given:-

Two cyclists start from the same point and ride in opposite directions. One cyclist ride twice as fast as the other. In three hours, they are 72 miles apart.

To find:-

Find the rate of each cyclist.

Solution:-

Let the speed of the slower cyclist be X miles per hour

Then the speed of the faster cyclist=twice the slower=2X miles per hour

Distance covered by slower cyclist in 3 hours

=speed×time

=(X)(3)=3X miles

Distance covered by faster cyclist in 3 hours

=Speed ×time

=(2X)(3)=6X miles

Now in 3 hours they are 72 miles apart

=>3X+6X=72

=>9X=72

=>X=72/9

=>X=8

2X=2×8=16

Solution:-

Speed or rate of the slower cyclist 8 miles per hour

Speed or rate of the faster cyclist 16 miles per hour

Used formula:-

Distance =Speed×Time

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